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pliss bantu kak tugas besokk:((
pliss bantu kak tugas besokk:((

1 Jawaban

  • in order to balance the carrying pole, he must put it on his shoulder right on the equilibrium position

    let point C be that position,

    and let the distance from A to C is x, so the distance from C to B is (1.5 - x), in meters

    we assume that A is the weight and B is the force

    since:
    weight * length of weight = force * length of force

    then
    5 * x  = 4,5 * (1,5 - x)
    5x = 6,75 - 4,5x
    9,5x = 6,75
    x = 0,75

    hence, he must put his shoulder right 0,75 meter from A

    hope this is clear enough and helpful