Matematika

Pertanyaan

Tolong bantu kak Sin 135° cos 330°-cos135° sin 150°/ 1+tan^2 240°

1 Jawaban

  • = {sin (135) cos (330) - cos (135) sin (150) }/ 1 + tan² (240)
    = {sin (180 - 45) cos (360 - 30) - cos ( 180 - 45) sin (180 - 30)} / 1 + tan² (180 + 60)
    = {sin 45 cos 30 - (- cos 45) sin 30}/1 + tan² 60
    = { √2/2 x √3/2 + √2/2 x 1/2 } / 1 + (√3)²
    = {(√6 + √2)/4} / 4
    = (√6 + √2)/16

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