Akar 128 dikurang 3 akar 50 ditambah 4 akar 8 dikurang 3 akar 18 adalah

[tex] = \sqrt{128} - 3 \sqrt{50} + 4 \sqrt{8} - 3 \sqrt{18} \\ = \sqrt{64 \times 2} - 3 \sqrt{25 \times 2} + 4 \sqrt{4 \times 2} - 3 \sqrt{9 \times 2} \\ = 8 \sqrt{2} - 15 \sqrt{2} + 8 \sqrt{2 } - 9 \sqrt{2} \\ = (8 - 15 + 8 - 9) \sqrt{2} \\ = - 8 \sqrt{2} [/tex]

√128-3√50+4√8-3√18

=√64.2 - 3√25.2 + 4√4.2 - 3√9.2
=8√2 - 3.5√2 + 4.2√2 - 3.3√2
=8√2- 15√2+8√2-9√2
= -7√2+-1√2
= -8√2