bantuin ya kaka ^ω^^ω^

1. hitung panjang keseluruhan pita merah dulu
[tex] = \frac{1}{3} \times 4 \\ = \frac{4}{3} [/tex]
hitung panjang total pita hijau:
[tex] = \frac{3}{4} \times 5 \\ = \frac{15}{4} [/tex]
total panjang pita keseluruhan :
[tex] = \frac{4}{3} + \frac{15}{4} \\ = ( \frac{4 \times 4}{3 \times 4} ) + ( \frac{15 \times 3}{4 \times 3} ) \\ = \frac{16}{12} + \frac{45}{12} \\ = \frac{61}{12} m \\ = 5 \: \frac{1}{12} m[/tex]

2. hitung total tanah yang dibagikan kepada anak2nya
[tex]2 \frac{4}{5} = \frac{14}{5} \\ = \frac{14}{5} \times 3 \\ = \frac{42}{5} [/tex]
maka sisa tanahnya adalah
[tex] = \frac{12}{1} - \frac{42}{5} \\ = ( \frac{12 \times 5}{1 \times 5} ) - \frac{42}{5} \\ = \frac{60}{5} - \frac{42}{5} \\ = \frac{18}{5} hektar \\ = 3.6 \: hektar[/tex]
3.
[tex]8 \frac{2}{5} = \frac{42}{5} \\ 4 \frac{1}{4} = \frac{17}{4} \\ 2 \frac{1}{10} = \frac{21}{10} [/tex]
maka tinggal dihitung:
[tex] = \frac{42}{5} - \frac{17}{4} - \frac{21}{10} \\ = \frac{42 \times 4}{5 \times 4} - \frac{17 \times 5}{4 \times 5} - \frac{21 \times 2}{10 \times 2} \\ = \frac{168 - 85 - 42}{20} \\ = \frac{41}{20} \\ = 2 \frac{1}{20} [/tex]

4. tinggal di jumlah semuanya
[tex]3 \frac{1}{4} = \frac{13}{4} \\ 5 \frac{3}{5} = \frac{28}{5} \\ 2 \frac{3}{10} = \frac{23}{10} [/tex]
maka:
[tex] = \frac{13}{4} + \frac{28}{5} + \frac{23}{10} \\ = \frac{(13 \times 5) + (28 \times 4) + (23 \times 2)}{20} \\ = \frac{65 + 112 + 46}{20} \\ = \frac{223}{20} \\ = 11 \frac{3}{20} [/tex]

5. tinggal di jumlah juga
[tex] = (5 + 2 + 4) + ( \frac{3}{4} + \frac{4}{7} + \frac{3}{8} ) \\ = 11 + ( \frac{(3 \times 14) + (4 \times 8) + (3 \times 7)}{56}) \\ = 11 + ( \frac{42 + 32+ 21}{56} ) \\ = 11 + \frac{95}{56} \\ = 11 + 1 \frac{39}{56} \\ = 12 \frac{39}{56} [/tex]