tolong bantu yaa caranya

a. sejajar garis 2x +5y = 0 melalui (-4,3)
2x +5y = 0
m1 = -2/5
karena sejajar maka m1 = m2
persamaan garis :
y-y1 = m(x-x1)
y -3 = -2/5(x+4)
5(y-3) = -2(x+ 4)
5y -15 = -2x -8
2x + 5y -7 =0

b. tegak lurus 3x -y = 6 melalui (2,-4)
3x -y = 6
m= 3
karena tegak lurus maka m1 x m2 = -1
3 x m2 = -1
m2 = -1/3
persamaan garis :
y-y1 = m(x-x1)
y+4 = -1/3 (x-2)
3(y+4) = -(x-2)
3y + 12 = -x +2
x + 3y + 10 = 0