Diketahui fungsi g(x)=4-3×. Tentukan: A. g^-1(×) B. (g°g^-1)(×) C. (g^-1°g)(×)

g (x) = 4 - 3x
= b - ax
b = 4, a = -3

A. g^-1 (x) = x - b / a
= x - 4 / -3

B. ( g o g^-1)(x) = g (g^-1(x))
= g ( x - 4 / -3)
= 4 - 3 (x - 4 / -3)
4(-3) - 3x + 12
= -------------------- Per
-3

- 12 - 3x + 12
= ------------------------
-3
= -3x / -3
= x

C. (g^-1 o g) (x) = g^-1 (g(x))
= g^-1 (4 - 3x)
= (4 - 3x) - 4 / -3
= -3x / -3
= x

maaf kalau salah :)
Koreksi lagi ya...