please kaka dibantu kaka besok dikumpul kaka

q1 = 2 mC = 2 × 10^-6 C
q2 = 6 mC = 6 × 10^-6 C
r = 3 mm = 3 × 10^-3 m
F?

penyelesaian:
F = k . q1 . q2 / r^2

F = 9×10^9 . 2×10^-6 . 6×10^-6 / (3×10^-3)^2

F = 108 × 10^-3 / 9 × 10^-6

F = 12 × 10^3 N

F = 12 kN