Tentukan jumlah setiap deret geometri berikut 1/4 + 1/2 + 1 + 2 +... +U10 Plisss bantuinnn pke caranya yh
Matematika
Hadju1
Pertanyaan
Tentukan jumlah setiap deret geometri berikut
1/4 + 1/2 + 1 + 2 +... +U10
Plisss bantuinnn pke caranya yh
1/4 + 1/2 + 1 + 2 +... +U10
Plisss bantuinnn pke caranya yh
2 Jawaban
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1. Jawaban yukeylnda
1/4, 1/2, 1, 2, 4, 8, 16, 32, 64, 128, 256, 512...
U¹ = 1/4
U² = 1/4 × 2 = 2/4 = 1/2
U³ = 1/2 × 2 = 1
U⁴ = 1 × 2 = 2
dst...
jumpa lagi⛺
follow and thanks ya.. -
2. Jawaban sulisriyanto
1/4 + 1/2 + 1 + 2 +... + U10
a = 1/4, r = 2
Sn = a(r^n - 1) / r - 1
= 1/4 (2^10 - 1) / 2 - 1
= 1/4 (1.024 - 1)
= 1/4 x 1.023
= 255,75