Matematika

Pertanyaan

Tentukan jumlah setiap deret geometri berikut


1/4 + 1/2 + 1 + 2 +... +U10

Plisss bantuinnn pke caranya yh

2 Jawaban

  • 1/4, 1/2, 1, 2, 4, 8, 16, 32, 64, 128, 256, 512...

    U¹ = 1/4
    U² = 1/4 × 2 = 2/4 = 1/2
    U³ = 1/2 × 2 = 1
    U⁴ = 1 × 2 = 2
    dst...

    jumpa lagi⛺
    follow and thanks ya..
  • 1/4 + 1/2 + 1 + 2 +... +  U10
    a = 1/4, r = 2

    Sn = a(r^n - 1) / r - 1
         = 1/4 (2^10 - 1) / 2 - 1
         = 1/4 (1.024 - 1)
         = 1/4 x 1.023
         = 255,75

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