f(x) = px + q f(-4) = -26 f(3) = 16 Nilai p + q adalah?

f(x) = px+q
f(-4) = -26

f(-4) = 4p+q
4p+q = -26 ........(1)

f(3) = px+q
3p + q = 16 .......... (2)

Eliminasi persamaan 1 dan 2

4p + q = -26
3p + q = 16
----------------- -
p = -42

Substitusi kan nilai p ke persamaan 1
4p +q = -26
4.(-42) +q = -26
-168 +q = -26
q = -26 - (-168)
q = -26 + 168
q = 142


Maka , nilai p+q sama dengan
p+q
-42 + 142 = 100

f(x) = px + q

f(-4) = p.(-4) + q = -26
f(3) = p.(3) + q = 16
= p. -12 = - 42
-12p =-42
p =-42+12
p = -30

q = ?
f(3) = p.x + q = 16
= -30.(3) + q = 16
= -60 + q = 16
q = 60+16=76
jadi Nilai p = -30
Nilai q = 72
jadi nilai p + q = -30 + 76
= 46

Kayaknya gituu
maaf kalau salah hehe