tolong dong sama caranya

[tex] {( \sqrt[3]{ \frac{1}{32} } )}^{4x} - 4 (\sqrt[3]{ \frac{1}{4} } ) {( \frac{4}{ {2}^{x} } )}^{3} = 0 \\ {( \frac{1}{ {2}^{5} } )}^{ \frac{4x}{3} } = {(2)}^{2} {( \frac{1}{ {2}^{2} } )}^{ \frac{1}{3} } {( {2}^{2 - x} )}^{3} \\ {2}^{ \frac{ - 20x}{3} } = {2}^{2 - \frac{2}{3} + 6 - 3x }[/tex]
-20x/3 = 8 - ⅔ -3x
-20x = 24 -2 -9x
-11x = 22
x = -2

1 - ¾x = 1 - ¾(-2) = 1 + 3/2 = 2½ (E)