Suatu fungsi dirumuskan dengan f(x)= px+q. Jika f(-2) =-11 dan f(5)=3 maka nilai p+q adalah

↪f(x) = px + q
↪f(-2) = -11
↪f(5)= 3

Ditanya nilai p + q

Jawaban :
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f(-2) = -11
px + q = -11
-2p + q = -11...... (1)

f(5) = 3
px + q = 3
5p + q = 3............... (2)


➡Persamaan 1 dan 2 eliminasi

-2p + q = -11
5p + q = 3
..................... -
-7p = -14
p = -14/7
p = 2



➡tentukan nilai q

-2p + q = -11
-2(2) + q = -11
-4 + q = -11
q = -11 + 4
q = -7


↪nilai p = 2
↪nilai q = -7


Maka, :
= p + q
= 2 + (-7)
= 2 - 7
= -5 ✔