nilai maksimum fungsi y=20x-5x²

Kelas 10 Matematika
Bab Fungsi Kuadrat

y = 20x - 5x²
a = -5; b = 20; c = 0

Sumbu simetri
= -b/2a
= -20/(2 . -5)
= 2

y = 20 . 2 - 5 . 2²
y = 40 - 20
y = 20

Nilai maksimum = 20