5 log 75+ 2 log 1 per 64+ 5 log 12 adalah..

Diketahui
ᵃlog b + ᵃlog d = ᵃlog (b x d)
ᵃlog b - ᵃlog d = ᵃlog (b/d)
ᵃlog bⁿ = n x ᵃlog b

Dimana :
⁵log 75 + ²log 1/64 + ⁵log 12
= ⁵log 75 x12 + ²log 1/64
= ⁵log 75 x12 + ²log (1/2^6)
= ⁵log 900 + ²log 2^-6
= ⁵log 900 + -6.²log 2
= ⁵log 5.5.36 + -6.²log 2
= ⁵log 5 + ⁵log 5 + ⁵log 36 + -6.²log 2
=⁵log 5 + ⁵log 5 + ⁵log 6² + -6.²log 2
= 1 + 1 + ⁵log 6² - 6
= -4 + ⁵log 6²