tolonh bantu dong kak klo bisa pakai cara

#ph larutan
#basa kuat
#XI semester 2

[Ca(OH)2] = m/Mr x 1000/mL
= 2,22/74 x 1000/5000
= 6.10-3 M

OH- = b Mb
= 2 x 6.10-3
= 12.10-3 M
= 1,2.10-2 M

poh = 2 - log 1,2

ph = 12 + log 1,2



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