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1 Jawaban

  • 5. CH3OH (Mr= 32) H2O (Mr= 18)

    Mol CH3OH = massa/Mr = 10/32 = 0,3125 mol

    Mol H2O = massa/Mr = 20/18 = 1,111 mol

    Fraksi CH3OH :

    Xt = nt/nt + np = 0,3125/0,3125+1,111 = 0,3125/1,4236 = 0,220

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