Jika
Matematika
muhammadridho28
Pertanyaan
Jika <BAC+<BDC+<BEC=150°, besar<BOC=
2 Jawaban
-
1. Jawaban sulisriyanto
∠BAC = ∠BDC = ∠BEC = a, karena menghadap busur yang sama.
Sehingga :
a + a + a = 150
3a = 150
a = 50°
Jadi ∠BOC = 2a
= 2(50)
= 100° -
2. Jawaban iyankick72
a + a + a = 150
50+50+50=150
a = 50°
Jadi ∠BOC = 2a
= 2×50
= 100°✔
#jadikanjawabaniniyangterbaik#