diketahui f(x) = x²+6x+5, g(x) = √x+4. dan h(x) = x²-5x+1. Rumus fungsi (g o f o y) (x) =

g∘f∘h)(x)​g(f(h(x)))​g(f(x​2​​−5x+1))​g((x​2​​−5x+1)​2​​+6(x​2​​−5x+1)+5)​g(x​4​​+25x​2​​+1−10x​3​​+2x​2​​−10x+6x​2​​−30x+6+5)​g(x​4​​−10x​3​​+33x​2​​−40x+12)​√​(x​4​​−10x​3​​+33x​2​​−40x+12)+4​​​​√​x​4​​−10x​3​​+33x​2​​−40x+16​​​​√​(x−4)​2​​(x−1)​2​​​​​​(x−4)(x−1)​x​2​​−5x+4​