Matematika

Pertanyaan

tolong yah dijawab kak
tolong yah dijawab kak

2 Jawaban

  • PQ² = 20²-12²
    PQ² = 400-144
    PQ = √256
    PQ = 16

  • [tex] {pq}^{2} = \sqrt{ {op}^{2} - {oq}^{2} } \\ {pq}^{2} = \sqrt{ {20}^{2} - {12}^{2} } \\ {pq}^{2} = \sqrt{400 - 144} \\ {pq}^{2} = \sqrt{256} \\ pq = 16[/tex]