tolong yah dijawab kak
Matematika
sucay1510
Pertanyaan
tolong yah dijawab kak
2 Jawaban
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1. Jawaban pemula106
PQ² = 20²-12²
PQ² = 400-144
PQ = √256
PQ = 16 -
2. Jawaban Christian261
[tex] {pq}^{2} = \sqrt{ {op}^{2} - {oq}^{2} } \\ {pq}^{2} = \sqrt{ {20}^{2} - {12}^{2} } \\ {pq}^{2} = \sqrt{400 - 144} \\ {pq}^{2} = \sqrt{256} \\ pq = 16[/tex]