10√3/√2: 10/5√3: 5/√6-√2: 5√3-√2/5√3+√2: √7+√5/3√7-√5: 3√3-√10/3√3+√10:
Matematika
ekaseptiana2
Pertanyaan
10√3/√2:
10/5√3:
5/√6-√2:
5√3-√2/5√3+√2:
√7+√5/3√7-√5:
3√3-√10/3√3+√10:
10/5√3:
5/√6-√2:
5√3-√2/5√3+√2:
√7+√5/3√7-√5:
3√3-√10/3√3+√10:
1 Jawaban
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1. Jawaban lisaaaliyah12
[tex]1. \: \: \: \: \: \frac{10 \sqrt{3} }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ = \frac{10 \sqrt{6} }{2} \\ = 5 \sqrt{6} \\ 2. \: \: \: \: \: \frac{10}{5 \sqrt{3} } \times \frac{5 \sqrt{ 3} }{5 \sqrt{3} } \\ = \frac{50 \sqrt{3} }{25 \sqrt{9} } \\ = \frac{50 \sqrt{3} }{25 \times 3} \\ = \frac{50 \sqrt{3} }{75} = \frac{2 \sqrt{3} }{3} \\ 3. \: \: \: \: \: \frac{5}{ \sqrt{6} - \sqrt{2} } \times \frac{ \sqrt{6} + \sqrt{2} }{ \sqrt{6} + \sqrt{2} } \\ = \frac{5( \sqrt{6} + \sqrt{2}) }{6 + \sqrt{12} - \sqrt{12} - 4 } \\ \frac{5( \sqrt{6} + \sqrt{2} )}{6 - 4} \\ = \frac{5( \sqrt{6} + \sqrt{2)} }{2} \\ [/tex]
maaf sisanya bisa mikir sendiri kan soalnya sudah malam otk sya lgi blank jdi ampe 3 aja yah