pH campuran 100mL larutan CH3COOH 0,5 M dengan 50mL larutan CH3COONa adalah 5-log 9. Tentukan konsentrasi CH3COONa. (Ka = 1,8 × 10^-5)

pH campuran = 5-log9
[H+]=9×10^-5

n CH3COOH=v.M=0.5M.100ml=50mmol
n CH3COONa=v.M=50.M = 50M mmol

[H+]=ka mmol CH3COOH/mmol CH3COONa.n
9×10^-5=1,8×10^-5 . 50/50M
9=1,8M
M=5M

jawab=5M