3log 5 × 25log 1/9 - (2log 10 - 2log 5) = ...

Kelas 10 Matematika
Bab Logaritma

^ = pangkat

³log 5 . ²⁵log (1/9) - (²log 10 - ²log 5)
= ²⁵log 5 . ³log (1/9) - (²log (10/5))
= ^(5²)log 5 . ³log 3⁻² - ²log 2
= (1/2) . ⁵log 5 . (-2) . ³log 3 - 1
= -1 - 1
= -2

= ³log 5 x  ⁵^² log 1/3² - ( ²log 2x5 -  ²log 5)
= ³log 5 x ⁵^² log 3⁻² - (²log 2 + ²log 5 - ²log 5)
= ³log 5 x ⁻²/₂ ⁵log 3 - ²log 2
= ³log 5 x - 1 / ³log 5 - 1
=  - 1 - 1
= - 2